请教matlab程序错误
本帖最后由 haorizi2012 于 2011-3-30 14:33 编辑%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% A LATTICE BOLTZMANN FORMULATION FOR THE ANALYSIS OF
% RADIATIVE HEAT TRANSFER PROBLEMS
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% Lattice Boltzmann sample, written in matlab
% Copyright (C) 2010-12-10 14:53:49 Zhao Lei .
% Address:
% E-mail: haorizi2008.cool@163.com
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
clear
clf
% RADIATION CONSTANS
ly = 51;
lx = 51;
delta_x= 1./(lx-1);
delta_y= 1./(ly-1);
delta_t= 1.0e-004;
sigma = 5.67e-008; % constant s is the geometric distance
Thot= 1;
Tcold = 0;
Ib = sigma*Thot.^4/pi ;% blackbody intensity
G = 4*pi.*Ib ; % volumetric absorption
IEq = G/(4*pi); % equilibrinm PDFs
beta= 1.0; % extinction coefficient
n =8;
alpha = pi/4; %
tPlot = 100; % iterations between successive graphical outputs
tStatistics = 10;% iterations between successive file accesses
Kn = delta_x*beta <= 0.05;% Kn number is smaller than a threshold value that ensures stability and accuracy
% D2Q8 LATTICE CONSTANTS
cx= ;
cy= ;
t = ones(1,8)*alpha/(2*pi); % weight
az= ;
= meshgrid(1:ly,1:lx);
ux= delta_x/delta_t; % velocity
uy= delta_y/delta_t;
omega = sqrt((cx*ux)*(cx*ux)'+(cx*uy)*(cx*uy)')*beta; % relaxation frequency
% INITIAL CONDITION FOR RADIATION:
IIn= ones(8,lx,ly); %8 is the direction number,2 is r
IOut = ones(8,lx,ly);
ts = 0;
% MAIN LOOP
while (ts<80000 && Kn <= 0.05 && abs((abs(IOut)-abs(IIn))./abs(IIn)))<1e-6 || ts<100
%BOUNDARY CONDITIONS FOR RADIATION:
for i=1:8
IIn (i , : ,1) = sigma*Thot^4/pi;% sigma is Stefan-Boltzmann constant
IOut(i , 1 ,:) = 0;
IOut(i ,lx ,:) = 0;
IOut(i ,: ,ly) = 0;
end
% COLLISION STEP
for i=1:8
IEq(i,:,:)= zeros(i,lx,ly);%让平衡分布函数IEq初始为同维的零矩阵
IEq(i,:,:)= IEq(i,:,:)+ reshape(t*reshape(IIn,8,lx*ly),i,lx,ly); % equilibrinm PDFs
IOut(i,:,:) = zeros(i,lx,ly);
IOut(i,:,:) = IIn(i,:,:) - omega .* (IIn(i,:,:)-IEq(i,:,:));
end
% STREAMING STEP RADIATION
for i=1:8
IIn(i,:,:) = circshift(IOut(i,:,:), );
tx= pi*sin(alpha/2)*cos(az(i)); %weight x direction
ty= pi*sin(alpha/2)*sin(az(i)); %weight y direction
end
ts = ts+1;
end
% radiative heat fluxes
Qx = sum(tx.*IOut);
Qy = sum(ty.*IOut);
% VISUALIZATION
if (mod(ts,tPlot)==0)
Q = reshape(sqrt(Qx.^2+Qy.^2),lx,ly);
imagesc(Q');colorbar
title('heat flux');
axis equal off; drawnow
end
耽误一下大家的时间,希望能得到大家的关注
回复 1 # haorizi2012 的帖子
你不说你的问题,光贴个程序出来,你想让网友如何关注? 回复 2 # mhkmars 的帖子
你运行一下就知道了啊,主要是IEq(i,:,:)= IEq(i,:,:)+ reshape(t*reshape(IIn,8,lx*ly),i,lx,ly);这句,
??? Index exceeds matrix dimensions. haorizi2012 发表于 2011-3-30 19:03 static/image/common/back.gif
回复 2 # mhkmars 的帖子
你运行一下就知道了啊,主要是IEq(i,:,:)= IEq(i,:,:)+ reshape(t*reshape(I ...
估计是你数组维数没有定义好, 你的错误原因是矩阵访问超出边界了。比如矩阵里面只要3个元素,你访问第四个就出现类似错误了。程序运行问题,你可以在M文件里面加断点,单步调试。 本帖最后由 ChaChing 于 2011-4-1 01:02 编辑
回复 3 # haorizi2012 的帖子
1. 请标题要明确!
2. Ref: 12F, 常见的程序出错问题整理 (eight)
http://forum.vibunion.com/forum/thread-46001-1-1.html
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