[求助]离心泵叶轮几何参数的优化
<FONT face="Times New Roman"><Palign=left>请高手帮我分析原因<BR>两个目标函数<BR></P>
<Palign=left><FONT face="Times New Roman">f<SUB>1</SUB>(X)=1.633+1591987x</FONT><SUB>4</SUB><FONT face="Times New Roman"><SUP>5.268</SUP>+12796x<SUB>4</SUB><SUP>2</SUP>-40179.44×sinx<SUB>3</SUB>/z-0.01755/</FONT>｛<FONT face="Times New Roman">x<SUB>7</SUB>×tanx<SUB>3</SUB>×</FONT>｝<FONT face="Times New Roman">+40.83+9174.45</FONT>【<FONT face="Times New Roman">147-4.34×10<SUP>-5</SUP>×</FONT>｛<FONT face="Times New Roman">23033×x<SUB>4</SUB><SUP>2</SUP></FONT><FONT face="Times New Roman">×(1-</FONT>π<FONT face="Times New Roman">sinx<SUB>3</SUB>/x<SUB>1</SUB>)-3.16×10<I ><SUP>-</SUP></I><SUP>2</SUP>/</FONT>｝<FONT face="Times New Roman"><SUP>2</SUP>/x<SUB>4</SUB><SUP>2</SUP>-4.33×10<SUP>-8</SUP></FONT><FONT face="Times New Roman">×</FONT>｛<FONT face="Times New Roman">1/-1/</FONT>｝<FONT face="Times New Roman">+2396366-5758.3x<SUB>5</SUB><SUP>2</SUP></FONT>】<FONT face="Times New Roman"><SUP>0.5</SUP>×</FONT>｛<FONT face="Times New Roman">23033×x<SUB>4</SUB><SUP>2</SUP>×(1-</FONT>π<FONT face="Times New Roman">sinx<SUB>3</SUB>/x<SUB>1</SUB>)-3.16×10<SUP>-2</SUP>/</FONT>｝<p></p></P>
<Palign=left><FONT face="Times New Roman">f<SUB>2</SUB>(X)=3.0×10<SUP>-8</SUP>×x<SUB>5</SUB><SUP>-4</SUP>+<BR>1.06×10<SUP>-9</SUP>/</FONT>｛<FONT face="Times New Roman">x<SUB>2</SUB><SUP>2</SUP>×x<SUB>5</SUB><SUP>2</SUP><SUP>2</SUP></FONT>｝<FONT face="Times New Roman">+564.08x<SUB>5</SUB><SUP>2<BR></SUP></FONT><p></p></P>
<Palign=left>约束条件<BR></P><FONT face="Times New Roman">
<P >4＜x1＜9，且x1取整数，5＜x2＜9，π/9＜x3＜2π/9，69＜x4＜86，20＜x5＜24，<p></p></P>
<P >5π/36＜x6＜2π/9，3＜x2＜5<p></p></P>
<P >function f=funy(x)<BR>f(1)=1.633+1591987*power(x(4),5.268)+12796*power(x(4),2)-40179.44*sin(x(3))/x(1)+40.83-1.755e-2/(tan(x(3))*x(7)*(1-x(1)*sqrt(1+power(x(3),2))/(pi*x(4))+9174.45*sqrt(147-4.34e-5*power((23033*power(x(4),2)*(1-pi*sin(x(3))/x(1)-3.16e-2/(x(2)*tan(x(3))*(1-x(1)*sqrt(1+power(cot(x(3)),2))),2)/x(4)-4.33e-8*(1/(power(x(2),2)*power(x(5),2)power((1-x(1)*sqrt(1+power(cot(x(6)),2)/(pi*x(5))),2)-1/(power(x(7),2)*power(x(4),2)power((1-x(1)*sqrt(1+power(cot(x(6)),2)/(pi*x(4))),2)+2396366-5758.3*power(x(5),2))*(23033*power(x(4),2)*(1-pi*sin(x(3))/x(1))-3.16e-2/(x(2)*tan(x(3))*(1-x(1)*sqrt(1+power(cot(x(3)),2)));<BR>f(2)=3e-8*power(x(5),-4)+1.06e-9/(power(x(2),2)*power(x(4),2)*power((1-x(1)*sqrt(1+power(x(3),2))/(pi*x(5))),2)+564.08*power(x(5),2);<BR>A=;<BR> b=';<BR>weight=abs(goal);<BR>lb=';<BR>x0=';<BR>options=optimset('LargeScale','off','Display','final','TolFun',1e-8,'TolX',1e-4);<BR>=fgoalattain(@funy,x0,goal,weight,A,b,lb,[],[])</FONT></P></FONT>
哈哈
不知道你的目标函数是什么
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