求：信号去噪的MATLAB程序及性能分析
我正在做毕业设计，请问谁有关信号去噪的MATLAB程序以及性能分析（信噪比、残差平方和最小、残差绝对值最小以及方差） 这两天搞毕业设计，编的用Matlab中的fft分析含噪声的信号，其中有直接FFT，时域同步平均后FFT，频域同步平均后FFT。可以参考。%%This procedure is to investigate the FFT of sine signal, sine signal with
%%noise.The sine signal with noise is treated by direct FFT,
%%FFT after piece-wise averaging in time domain, and FFT after
%%piece-wise averagingfrequency domain
%%
clear all
pack
w=10;
t=0:(2*pi/w/500):(300*2*pi/w);
x=sin(w*t);
n=length(t);
ss=888;
randn('seed',ss);
z=randn(1,n);
z1=z-mean(z);
z2=z1/max(abs(z1));
z2=z2*500;
figure(1)
plot(t,x)% The sine signal without noise
fre=(1/(2*pi/w/500))*(1:n)/n;
nn=fix(n/2);
y1=fft(x);% The FFT of sine signal without noise
y1=(abs(y1)).^2/n;
y2=y1(2:(nn+1));
fre1=2*pi*fre(1:nn);
figure(2)
plot(fre1,y2)
x=x+z2;
y1=fft(x);% The FFT of sine signal with noise
y1=(abs(y1)).^2/n;
y2=y1(2:(nn+1));
figure(3)
plot(fre1,y2) %The sine signal with noise
%% Averaging in time domain
M=10000;
xx=zeros(1,M);
m1=1;m2=M;
nnnn=fix(300*500/M);
for nnn=1:nnnn
xxx=x(m1:m2);
xx=xx+xxx;
m1=m1+M;
m2=m2+M;
end
fre=(1/(2*pi/w/500))*(1:M)/M;
nn=fix(M/2);
xx=xx/nnnn;
y1=fft(xx);
y1=(abs(y1)).^2/M;
y2=y1(2:(nn+1));
fre1=2*pi*fre(1:nn);
figure(4)
plot(fre1,y2)
% Next is averaging in frequency domain
% In fact, the averaging in time domain is identical with that in frequency
% domain
MM=10000;
xx=zeros(1,MM);
m1=1;m2=MM;
nnnn=fix(300*500/MM);
for nnn=1:nnnn
xxx=x(m1:m2);
xxx=fft(xxx);
%xxx=sqrt((abs(xxx)).^2);
xx=xx+xxx;
m1=m1+MM;
m2=m2+MM;
end
y1=xx/nnnn;
y1=(abs(y1)).^2/MM;
fre=(1/(2*pi/w/500))*(1:MM)/MM;
nn=fix(MM/2);
y2=y1(2:(nn+1));
fre1=2*pi*fre(1:nn);
figure(5)
plot(fre1,y2) 谢谢呀!你的毕业设计是做什么的 谢谢，我在做小波去噪，参考下
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