请教各位大大，怎样画求导分段函数的图
曲线是这样的分段函数f0=3*x0.^5-4*x0.^4-3*x0.^3+10;
x0∈
f1=53*x1.^5-400*x1.^4+1163*x1.^3-1622*x1.^2+1080*x1-268;
x1∈
f2=55*x1.^5-692*x2.^4+3437*x2.^3-8418*x2.^2+10160*x2-4828;
x2∈
f3=21*x3.^5-374*x3.^4+2647*x3.^3-9300*x3.^2+16208*x3-11200;
x3∈
f4=-9.5*x4.^5+210*x4.^4-1847.5*x4.^3+8090*x4.^2-17640*x4+15328;
x4∈
f5=-53*x5.^5+1458.5*x5.^4-16010*x5.^3+87627.5*x5.^2-239140*x5+260328;
x5∈
f6=-61*x6.^5+1987.5*x6.^4-25852*x6.^3+167799.5*x6.^2-543484*x6+702696;
x6∈
f7=-20.5*x7.^5+775*x7.^4-11702.5*x7.^3+88220*x7.^2-332000*x7+498954;
x7∈
急问：怎么画出他的一次导数的图。。 每一段diff，两段函数的转折处根据间断点的定义进行。 :@) :@) :@) 谢谢~~
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