fprintf中 '\n'无法实现换行？？
如题两个矩阵 Num1(11,11),Num2(11,21)
for j=1:11 %（按列循环，写入文本）
fprintf(fid,'%2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d\n',Num1(:,j));
end
fclose(fid);
fid=fopen('Num2.txt','wt');
for jj=1:21%（按列循环，写入文本）
fprintf(fid,'%2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d\n',Num2(:,jj));
end
fclose(fid)
运行后Num1.txt 中数据 可以实现换行，有11行 11列
但Num1.txt 中数据只有1行 ？
请问，这个问题怎么解决？
谢谢 这个问题解决了，是我自己搞错了，
fprintf 是按列写入的，Num2(11,21)有11行，因此应该是如下程序
fid=fopen('Num2.txt','wt');
for jj=1:21%（按列循环，写入文本）
fprintf(fid,'%2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d\n',Num2(:,jj));
end
fclose(fid) 这样也可以!?
fid=fopen('Num2.txt','wt');
for jj=1:11%（按列循环，写入文本）
fprintf(fid,'%2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d %2d\n',Num2(jj,:));
end
fclose(fid)
页:
[1]