请教dingda关于批量处理问题
想要求一个方程组，但其中的一个变量S可以取300到1000之间的任何值，步长为10，一次一次改S的值很麻烦，不知道能不能批处理，请dingda先生给予解决，谢谢啦。。。Parameter x,y,z;
constant S;
Function (2629.32072130138*x+0.676902938787872*x^2+2.06200660659653*10^(-4)*x^3-1.03386752205615*10^(-7)*x^4)-(2629.32072130138*S+0.676902938787872*S^2+2.06200660659653*10^(-4)*S^3-1.03386752205615*10^(-7)*S^4)+y*10^3*(-188.127606061783-0.0724019483237287*x+4.27818764486488*10^(-5)*x^2-7.97241646880469*10^(-9)*x^3)+z*10^3*(-146.463309091062-0.0699590675983468*x+2.73132867122831*10^(-5)*x^2-1.89277389234656*10^(-9)*x^3)=0;
exp((203.313957575831-0.187374285159722*x-6.36978438221116*10^(-5)*x^2+2.05433177929587*10^(-8)*x^3)/(8.314*x)/1000)=(y+2*z)*(26+y+z)*(100-2*y-2*z)^2/(7-y)/(59-3*y-4*z)^3/100;
exp((161.469181816515-0.139830396262278*x-7.39304195921339*10^(-5)*x^2+2.22226107277689*10^(-8)*x^3)/(8.314*x)/1000)=(y+2*z)^2*(26+y+z)*(100-2*y-2*z)^2/(2-z)/(59-3*y-4*z)^4/100;
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