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[编程技巧] 关于matlab中交互输入的问题??

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发表于 2007-3-24 00:00 | 显示全部楼层 |阅读模式

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本人刚刚学习matlab,正在编写一个扫雷的程序,还不会gui,是基于字符的,可以自己玩,也可以让电脑来自动扫!

不过在input上遇到了问题,每次运行到input 语句的时候显示如下:

??? Index exceeds matrix dimensions.

Error in ==> minesweeper at 11
    xx=input('Please input x!');

希望大家帮个忙!!

程序如下(未完成):

function step=minesweeper(x,y,input)%falied!
tag=input('1-Play by yourself!  2-Play by AI!');
matrix=minemap(x,y,input);
matrix1=zeros(x,y);
matrix1=matrix1-100;%Matrix1 is the matrix that you can see on screen!
disp(matrix1);
have=0;
if tag==1
  while check(have,matrix1,matrix)~=input
    have=check(have,matrix1,matrix);
    xx=input('Please input x!');
    yy=input('Please input y!');
    ju=input('please input judgement:1 0r 0!');
    matrix1=returnmap(matrix,xx,yy,ju);
  end
if have==input
     disp('You have successed!!');
else
     disp('To be continued.......');
end
elseif tag==2
  step=autoplay(matrix);  
  return;
end



function step=autoplay(inmatrix)%failed!
step=1;
[m,n]=size(inmatrix);
x=round(rand*(m-1))+1;
y=round(rand*(n-1))+1;
mat=returnmap(inmatrix,x,y);
if mat==0
    step='Failed';
    return;
end
while mat~=0 %?????
   
end

   
   
   
function outmatrix=minemap(x,y,input)%successful!
%First,we have to make the out!
totol=x*y;
out(1,1)=round(rand*(totol-1))+1;
for i=2:1:input
    long=length(out);tapp=1;
    while tapp==1
       tap=1;
       number=round(rand*(totol-1))+1;
       for j=1:1:long
           if out(1,j)==number
               tap=0;
               break;
           end
       end
       if tap==1
       out(1,i)=number;
       tapp=0;
       end
    end
end
%The out has been finished successfully!
outmatrix=zeros(x,y);
long=length(out);
for i=1:1:long
    outmatrix(out(i))=-20;
end
xx=zeros(1,y);yy=zeros(x+2,1);
temp=[xx;outmatrix;xx];
outsecond=[yy,temp,yy];
for i=2:1:x+1
    for j=2:1:y+1
        if  outsecond(i,j)<0
            outsecond(i-1,j)=outsecond(i-1,j)+1;
            outsecond(i+1,j)=outsecond(i+1,j)+1;
            outsecond(i,j-1)=outsecond(i,j-1)+1;
            outsecond(i,j+1)=outsecond(i,j+1)+1;
            outsecond(i-1,j-1)=outsecond(i-1,j-1)+1;
            outsecond(i-1,j+1)=outsecond(i-1,j+1)+1;
            outsecond(i+1,j-1)=outsecond(i+1,j-1)+1;
            outsecond(i+1,j+1)=outsecond(i+1,j+1)+1;
        end
    end
end
outmatrix=outsecond(2:x+1,2:y+1);



function outmatrix=returnmap(mat,x,y,ju)%failed!
%x and y are coordinates,but ju is a judgement,one means yes but means no!
outmatrix=mat;
if mat(x,y)<0&&ju==0
    outmatrix=0;
    return;% You have failed!
elseif mat(x,y)>0&&ju==0
    %100 means having known but -100 means unknown,88 means maybe a bomb!
    outmatrix(x,y)=100;
    outmatrix=inmloop(mat,x,y);
elseif mat(x,y)>0&&ju==1
    outmatrix(x,y)=88;
elseif mat(x,y)<0&&ju==1
    outmatrix(x,y)=88;
end
%to be continued!






function  outmatrix=loop(mat,x,y)%failed!      
% function of loop is a recursion!
inmat=mat;
tempx=[x-1  x-1  x-1    x      x       x+1  x+1   x+1];
tempy=[y-1   y   y+1  y-1  y+1    y-1    y      y+1];
for i=1:1:8
     while tempx(i)>0&&tempy(i)>0
%100 means having known but -100 means unknown!
       if  inmat(tempx(i),tempy(i))==0
           temp1=temp(i)-x;temp2=temp(i)-y;
           for j=1:1:8
               inmat(tempx(j)+temp1,tempy(j)+temp2)=100;%?????
           end
           inmat=loop(inmat,tempx(i),tempy(i));
       else
           inmat(tempx(i),tempy(i))=-100;
       end
     end
end
outmatrix=inmat;

function  success=check(have,inmat,matrix)
success=have;
[x,y]=size(inmat);
    for i=1:1:x
        for j=1:1:y
            if inmat(x,y)==100&&matrix(x,y)<0
                success=success+1;
            end
        end
    end
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发表于 2007-3-24 09:59 | 显示全部楼层
xx=input('Please input x!');



你希望输入的是什么东西
 楼主| 发表于 2007-3-24 13:42 | 显示全部楼层
问题解决!
谢谢大家!!
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