求助：关于KPCA的matlab程序

betty822

如下2*2非线性系统，某时刻u2发生故障，用KPCA进行故障检测。谁能给点提示该如何编程~~   
y1(t)=[u1(t)+u2(t)]2;(2为平方的意思）
y2(t)=[u1(t)-2u2(t)]2;(2为平方的意思）

penghx

:lol

% Kernel PCA toy example for k(x,y)=exp(-||x-y||^2/rbf_var), cf. Fig. 4 in
% @article{SchSmoMue98,
%   author    = "B.~{Sch\"olkopf} and A.~Smola and K.-R.~{M\"uller}",
%   title     = "Nonlinear component analysis as a kernel Eigenvalue problem",
%   journal =         {Neural Computation},
%   volume    = 10,
%   issue     = 5,
%   pages     = "1299 -- 1319",
%   year      = 1998}
% This file can be downloaded from http://www.kernel-machines.org.
% Last modified: 4 July 2003


% parameters
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
rbf_var = 0.1;
xnum = 4;
ynum = 2;
max_ev = xnum*ynum;
% (extract features from the first <max_ev> Eigenvectors)
x_test_num = 15;
y_test_num = 15;
cluster_pos = [-0.5 -0.2; 0 0.6; 0.5 0];
cluster_size = 30;

% generate a toy data set
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
num_clusters = size(cluster_pos,1);
train_num = num_clusters*cluster_size;
patterns = zeros(train_num, 2);
range = 1;
randn('seed', 0);
for i=1:num_clusters,
  patterns((i-1)*cluster_size+1:i*cluster_size,1) = cluster_pos(i,1)+0.1*randn(cluster_size,1);
  patterns((i-1)*cluster_size+1:i*cluster_size,2) = cluster_pos(i,2)+0.1*randn(cluster_size,1);
end
test_num = x_test_num*y_test_num;
x_range = -range:(2*range/(x_test_num - 1)):range;
y_offset = 0.5;
y_range = -range+ y_offset:(2*range/(y_test_num - 1)):range+ y_offset;
[xs, ys] = meshgrid(x_range, y_range);
test_patterns(:, 1) = xs(:);
test_patterns(:, 2) = ys(:);
cov_size = train_num;  % use all patterns to compute the covariance matrix

% carry out Kernel PCA
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
for i=1:cov_size,
  for j=i:cov_size,
    K(i,j) = exp(-norm(patterns(i,:)-patterns(j,:))^2/rbf_var);
    K(j,i) = K(i,j);
  end
end
unit = ones(cov_size, cov_size)/cov_size;
% centering in feature space!
K_n = K - unit*K - K*unit + unit*K*unit;

[evecs,evals] = eig(K_n);
evals = real(diag(evals));
for i=1:cov_size,
  evecs(:,i) = evecs(:,i)/(sqrt(evals(i)));
end

% extract features
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%  do not need the following here - only need test point features
%unit_train = ones(train_num,cov_size)/cov_size;
%for i=1:train_num,
%  for j=1:cov_size,
%    K_train(i,j) = exp(-norm(patterns(i,:)-patterns(j,:))^2/rbf_var);
%  end
%end
%K_train_n = K_train - unit_train*K - K_train*unit + unit_train*K*unit;
%features = zeros(train_num, max_ev);
%features = K_train_n * evecs(:,1:max_ev);

unit_test = ones(test_num,cov_size)/cov_size;
K_test = zeros(test_num,cov_size);
for i=1:test_num,
  for j=1:cov_size,
    K_test(i,j) = exp(-norm(test_patterns(i,:)-patterns(j,:))^2/rbf_var);
  end
end
K_test_n = K_test - unit_test*K - K_test*unit + unit_test*K*unit;
test_features = zeros(test_num, max_ev);
test_features = K_test_n * evecs(:,1:max_ev);

% plot it
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
figure(1); clf
for n = 1:max_ev,
  subplot(ynum, xnum, n);
  axis([-range range -range+y_offset range+y_offset]);
  imag = reshape(test_features(:,n), y_test_num, x_test_num);
  axis('xy')
  colormap(gray);
  hold on;
  pcolor(x_range, y_range, imag);
  shading interp
  contour(x_range, y_range, imag, 9, 'b');
  plot(patterns(:,1), patterns(:,2), 'r.')
  text(-1,1.65,sprintf('Eigenvalue=%4.3f', evals(n)));
  hold off;
end

penghx

原始文献 Nonlinear component analysis as a kernel Eigenvalue problem
可以从IEEE 数据库当中查到！

dyhkxydfbb

penghx 发表于 2008-10-22 15:47

                               
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原始文献 Nonlinear component analysis as a kernel Eigenvalue problem
可以从IEEE 数据库当中查到！

这个运行结果出的图该如何理解啊？
我曾经把这个代码用在意大利葡萄酒数据上，发现效果不好啊

simon21

dyhkxydfbb 发表于 2012-11-27 13:03

                               
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这个运行结果出的图该如何理解啊？
我曾经把这个代码用在意大利葡萄酒数据上，发现效果不好啊

KPCA所提取的各特征的物理意义很不明确，所以很难理解，这也是KPCA的最大缺陷之一